Find the Integral tan (3x) tan (3x) tan ( 3 x) Let u = 3x u = 3 x Then du = 3dx d u = 3 d x, so 1 3du = dx 1 3 d u = d x Rewrite using u u and d d u u Tap for more steps Let u = 3 x u = 3 x Find d u d x d u d xYou don't Given the struggles this integral has caused on mathstackexchange, there's a high probability this doesn't have an antiderivative in terms of elementary functions, and neither a closed form for its value (substituting gives Integrate the following with respect to x (i) 9xe^3x (ii) x sin 3x (iii) 25xe^5x (iv) x sec x tan x asked in Integral Calculus by RamanKumar (499k points) integral calculus;

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Integral tan(x/2) substitution-Integral of cos^2 (x) \square!Best Answer this can be integrated using by parts technique let 1/x=d v then logx dx =v on integrating let tanx=u sec^2xdx=du integral udv= uvintegral vdu=logxtanx integral logxsec^2xdx so integral tanx/x dx= logxtanx integral logx sec^2xdxA now consider the second term in the rhs



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(integral of the square root of tangent) Thank you in advance, Panos I can't do anything else than the obvious tan=sin/cos I really can't figure out which differentiation is giving you the sin^(1/2) * cos^(1/2) ( Last edited Answers and Replies #2 Dick integral of (tan x)^(1/2) ? tanxxC We will use the Trigo Identity sec^2x=tan^2x1 Hence, int(tanx)^2 dx=int tan^2xdx=int (sec^2x1)dx =int sec^2xdxint 1 dx=tanxxC Enjoy Maths!
Originally Answered How do I evaluate the integral \int_{0}^{\frac{\pi}{2}}\frac{1}{(1x^2)(1\tan x)} d{x}?Originally Answered What is the integral of tan (ln x)? In this video, I demonstrate how to find the antiderivative or the integral of tan^2(x) This would normally be quite a difficult integral to solveHowever,
\\int \tan^{2}x\sec{x} \, dx\ > < Ex 76, 13 Integrate the function tan^(−1) 𝑥 ∫1 〖" " tan^(−1) 𝑥" " 〗 𝑑𝑥=∫1 〖(tan^(−1) 𝑥) 1𝑑𝑥 " " 〗 = tan^(−1) 𝑥∫1Figure 1 Graphs of 2tan2 x (blue) and sec x (red) In fact, that is the case sin2 x tan2 x = cos2 x 1 2− cos x = cos2 x = sec 2 x − 1 1 2 1 2 1 We conclude that tan x = sec and so the two results are equiva 2 2 x − 2 lent up to an added constant Both answers are correct 2



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In doing this, the Integral Calculator has to respect the order of operations A specialty in mathematical expressions is that the multiplication sign can be left out sometimes, for example we write "5x" instead of "5*x" The Integral Calculator has to detect these cases and insert the multiplication signGet stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!To integrate 2tanx, also written as ∫2tanx dx, we focus on the constant 2 and how it impacts the integration A constant can be brought outside of the integral sign to simplify the integration We use a standard proof from formula booklet, as shown above, and therefore ∫tanx dx = lncosx C




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∫ tanx x dx = ∫ x 1 3x3 2 15x5 − 17 315x7 62 25x9 x dx ∴ ∫ tanx x dx = ∫1 1 3 x2 2 15x4 − 17 315x6 62 25x8 ∴ ∫ tanx x dx = x 1 3 x3 3 2 15 x5 5 − 17 315 x7 7 62 25 x9 9243 The Substitution z = tan (x/2) Suppose our integrand is a rational function of sin (x) and cos (x) After the substitution z = tan (x / 2) we obtain an integrand that is a rational function of z, which can then be evaluated by partial fractionsIf you let u=tanx in integral (tan^2)x you get integral u^2 dx which is not (u^3)/3 c since du= sec^2x dx




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As there is no way to immediately integrate tan^2 (x) using well known trigonometric integrals and derivatives, it seems like a good idea would be writing tan^2 (x) as sec^2 (x) 1 Get an answer for 'Prove the following reduction formula integrate of (tan^(n)x) dx= (tan^(n1)x)/(n1) integrate of (tan^(n2))dx' and find homework help for other Math questions at eNotesIntegtan (in x) dx =x tan (in x) integxd {tan ( in x)} (since integ u dv = uv integv du) =x tan ( in x) integx/ (1x^2) dx =x tan ( in x) 1/2integ2x/ (1x^2) dx = x tan (in x) log ( 1x^2) c 613 views · View 1 Upvoter




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